WebThe middle term in the expansion of (x− x1)18 is A 18C 9 B − 18C 9 C 18C 10 D − 18C 10 Medium Solution Verified by Toppr Correct option is B) The general term in the expansion (x− x1)18 is given by T r+1= 18C r(x) 18−r(− x1)r Here, n=18 ∴ The middle term is T 9+1, where r=9 ∴T 9+1= 18C 9(−1) 9x 18−2r =− 18C 9x 18−18=− 18C 9 WebAug 24, 2024 · Best answer Given, expansion is (x − 1 x)2n ( x - 1 x) 2 n. This Binomial expansion has even power. So, this has one middle term. i.e., ( 2n 2 + 1) ( 2 n 2 + 1) th term = (n + 1)th = ( n + 1) t h term T n+1 =.2n C n(x)2n−n( − 1 x)n =.2n C nxn( − 1)n x−n T n + 1 =. 2 n C n ( x) 2 n - n ( - 1 x) n =. 2 n C n x n ( - 1) n x - n
How do you expand (x+y)^10? Socratic
WebNov 13, 2024 · The constant term in the expansion of \((x+\frac{2}{x})^6\) is: (a) 156 (b) 165 (c) 162 (d) 160. algebra; class-11; Share It On Facebook Twitter Email. 1 Answer +1 vote . answered Nov 13, 2024 by ... ∴ Constant term occurs only in … WebMar 16, 2024 · Transcript. Ex 8.2, 8 Find the middle terms in the expansions of (𝑥/3+9𝑦)^10 Number of terms n = 10 Since n is even. There will be one middle term Middle term = 𝑛/2 + … novant cardiology salisbury nc
Show that the middle term in the expansion of (x - 1/x)^2n
WebAnswer (1 of 2): It is good if you do not have to rely on formulas to do stuff like this. If you know how to expand these binomial series it is no big deal! Watch this simple method: It does not matter if you need to write the 3 or 4 terms leading up to the one you are wanting. It … WebMar 4, 2024 · Find the term independent of x in the expansion of ( √x/√3 + √3/ 2x^2 )^10. asked Jan 17, 2024 in Binomial Theorem by Babli ( 4.0k points) binomial theorem WebThe term independent of x in the expansion of x + 1 x 2 3 - x 1 3 + 1 - x - 1 x - x 1 2 10, x ≠ 1, is equal to Solution Step 1: Simplify the given expression: Given expression is x + 1 x 2 3 - x 1 3 + 1 - x - 1 x - x 1 2 10 and x ≠ 1. The above expression can be simplified as follows how to slow dance video